A disc has mass 'M' and radius 'R'. The axis of rotation passes through a point P in the plane of the disc, which is at a distance 'x' $(x \lt R)$ from the center of the disc and perpendicular to the plane of the disc. M.I. of disc about the axis of rotation is found to be $MR^2$. The value of 'x' is
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If $\vec{r}$ is a position vector of the body and $\vec{p}$ is linear momentum, $\vec{r}=2\hat{i}+3\hat{j}-3\hat{k}$ and $\vec{p}=2\hat{i}+4\hat{j}-5\hat{k}$.
The angular momentum of the body is
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