A particle is projected at $60^\circ$ to the horizontal with kinetic energy 'K'. The kinetic energy at the highest point is $\left(\cos 60^0 = \dfrac{1}{2}\right)$
MHT-CET
Motion In Two Dimensions question bank (Physics)
Practice 122 free MHT-CET Physics - Motion In Two Dimensions questions with answers and step-by-step solutions.
Q1.
Verified Answer & Solution Locked
Sign in to your free student account to reveal verified answers, instant hints, and detailed explanations.
Q2.
Two particles are separated by a horizontal distance $'x'$ as shown. They are projected at the same time as shown with different initial speeds. The time after which the horizontal distance between them becomes zero is
$\left\{ \cos 30^\circ = \dfrac{\sqrt{3}}{2}, \cos 60^\circ = \dfrac{1}{2} \right\}$
Show answer & solution
Verified Answer & Solution Locked
Sign in to your free student account to reveal verified answers, instant hints, and detailed explanations.
Protected Questions
Unlock All 122 Questions in Motion In Two Dimensions
Log in or sign up free to access every question with complete solutions, create chapter practice tests, and track your performance.
Sign up free to access all 122 questions
Unlock every Motion In Two Dimensions question, generate papers, and practice at your own pace.