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Q1.

If $A=\left[\begin{array}{lll}1 & 2 & 1 \\ 2 & 1 & 0\end{array}\right], B=\left[\begin{array}{ll}1 & 2 \\ 2 & 1 \\ 0 & 1\end{array}\right]$, then $(\mathrm{AB})^{-1}$ is

(A)

$\left(\frac{1}{5}\right)\left[\begin{array}{ll}5 & -5 \\ 4 & -5\end{array}\right]$

(B)

$\left(\frac{1}{5}\right)\left[\begin{array}{cc}5 & -5 \\ -4 & 5\end{array}\right]$

(C)

$\left(\frac{1}{5}\right)\left[\begin{array}{cc}5 & -5 \\ 4 & 5\end{array}\right]$

(D)

$\left(\frac{1}{5}\right)\left[\begin{array}{cc}5 & -5 \\ -4 & -5\end{array}\right]$

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Q2.

If $A=\left[\begin{array}{ll}1 & 1 \\ 1 & 2\end{array}\right], \quad B=\left[\begin{array}{ll}4 & 1 \\ 3 & 1\end{array}\right], \quad$ then $(A+B)^{-1}=$

(A)

$\frac{1}{7}\left[\begin{array}{ll}3 & 2 \\ 4 & 5\end{array}\right]$

(B)

$7\left[\begin{array}{cc}3 & 2 \\ 4 & 5\end{array}\right]$

(C)

$\frac{1}{7}\left[\begin{array}{cc}3 & -2 \\ -4 & 5\end{array}\right]$

(D)

$7\left[\begin{array}{cc}3 & -2 \\ -4 & 5\end{array}\right]$

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