Ellipse question bank (Mathematics)

If foci of the ellipse $\frac{x^{2}}{16}+\frac{y^{2}}{b^{2}}=1\left(b^{2} \lt 16\right)$ and the hyperbola $\frac{x^{2}}{144}-\frac{y^{2}}{81}=\frac{1}{25}$ coincide, then the value of $b^{2}$ is

The co-ordinates of foci of the ellipse $16 x^{2}+9 y^{2}=144$ are