"P" is a hydrocarbon of molecular formula: C$_8$H$_{14}$. On ozonolysis, "P" forms "Q". "Q" on treatment with alkali under reflux condition produces "R", which on treatment with I$_2$/NaOH gives a yellow precipitate. Acidification of the solution gives "S". The structure of "S" is given below:
The correct structure of "P" is
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Compound (X) [styrene] is subjected to the sequence of reactions as shown above: (i) $Br_2/CHCl_3$ (ii) $NaNH_2$ excess (iii) $CH_3I$ (iv) $H_2$, $Na/NH_3$ $(l)$, giving Major Product (Y). Molar mass of the major product (Y) formed is ______ g mol$^{-1}$.
(Given molar mass in g mol$^{-1}$ C:$12$, H: $1$, O: $16$)
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