Match List-I with List-II.
| List-I Electronic configuration of neutral atom (where $n=2$) | List-II $1^{st}$ Ionization Energy (kJ mol$^{-1}$) |
|---|---|
| A. $ns^2$ | I. $2080$ |
| B. $ns^2np^1$ | II. $899$ |
| C. $ns^2np^3$ | III. $800$ |
| D. $ns^2np^6$ | IV. $1402$ |
Practice 863 free Engineer & Medical Chemistry - Classification of Element questions with answers and step-by-step solutions.
Match List-I with List-II.
| List-I Electronic configuration of neutral atom (where $n=2$) | List-II $1^{st}$ Ionization Energy (kJ mol$^{-1}$) |
|---|---|
| A. $ns^2$ | I. $2080$ |
| B. $ns^2np^1$ | II. $899$ |
| C. $ns^2np^3$ | III. $800$ |
| D. $ns^2np^6$ | IV. $1402$ |
Given below are two statements:
Statement I: Aluminium is more electropositive than thallium as the standard electrode potential value of $E^{\circ}_{\text{Al}^{3+}/\text{Al}}$ is negative and $E^{\circ}_{\text{Tl}^{3+}/\text{Tl}}$ is positive.
Statement II: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason boron forms covalent compounds only and aluminium forms $\text{Al}^{3+}$ ion.
In the light of the above statements, choose the correct answer from the options given below
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